I'm currently havin an issue with the following code:
<form action="" method="post">
<input type="text" name="term" placeholder="Search Terms"/>
<select id=""drop"" name="drop"">
<option value="CODE">Code</option>
<option value="SCINAME">Scientific Name</option>
<option value="COLLECTOR">Holder</option>
<option value="DATA">Data</option>
</select>
<br/>
<button type="submit" class="button primary">Search</button>
</form>
<?php
if (!empty($_REQUEST['term'])) {
$term = mysql_real_escape_string($_REQUEST['term']);
$drop = ($_REQUEST['drop']);
$sql = "SELECT * FROM ANIMAIS WHERE '%".$drop."%' LIKE '%".$term."%'";
$r_query = mysql_query($sql);
while ($row = mysql_fetch_array($r_query)){
echo '<br />code: ' .$row['CODE'];
echo '<br />Name: ' .$row['SCINAME'];
echo '<br /> Colector: '.$row['COLLECTOR'];
echo '<br /> Local: '.$row['LOCAL'];
echo '<br /> Data: '.$row['DATA'];
echo '<br /> Descr: '.$row['DESCRIPTION'];
echo '<br />';
}
}
?>
The problem is that the code does not "run" the $drop variable, but if i remove the dropdown list from the form and change the following line:
$sql = "SELECT * FROM ANIMAIS WHERE '%".$drop."%' LIKE '%".$term."%'";
to
$sql = "SELECT * FROM ANIMAIS WHERE SCINAME LIKE '%".$term."%'";
It does work, but searching on the SCINAME column, what i wan't do is allowing the dropdown list to select wich SQL column to query, but the actual solution isn't working so well.
Thanks in advance for all help.
Aucun commentaire:
Enregistrer un commentaire